To plot the path of the particle, we need to find the expression for x in terms of t. We know that the velocity v_x is given by: vx=dxdt=50−16t𝑣𝑥=𝑑𝑥𝑑𝑡=50−16𝑡 Integrating with respect to t, we get: ∫dx=∫(50−16t)dt∫𝑑𝑥=∫(50−16𝑡)𝑑𝑡 x=50t−8t2+C𝑥=50𝑡−8𝑡2+𝐶 Given that x = 0...

• If the motor is rated at 19kW, is the motor sufficient to drive the two loads? • The translational motion load now has to lift a weight of 1200 kg at the same speed of 1.5m/s. Is the motor still capable to drive both loads at the same motor speed of 1420 rpm? Answer...

Answer: To analyze the beam described in the problem and to draw the shear force and bending moment diagrams, follow these steps: Given Data Loads: 5 kN 2 kN 3 kN 4 kN 25 kN/m (Uniformly Distributed Load, UDL) for 2 m 25 kN/m (UDL) for 2 m 10 kN/m (UDL) for 1 m Beam...

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